# Product and Quotient of Powers Laws  Rating

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## Basics on the topicProduct and Quotient of Powers Laws

After this lesson, you will be able to simplify exponential expressions involving multiplication and division.

The lesson begins with an illustration of why we can add exponents when multiplying numbers in exponential form, with the same base. It concludes with why we can subtract exponents when dividing numbers in exponential form, with the same base.

Learn how to multiply and divide exponential expressions by helping Archimedes calculate the number of grains of sand in the universe!

This video includes key concepts, notation, and vocabulary such as: Laws of Exponents (a set of rules that govern arithmetic with exponents); Product of Powers Law (when multiplying powers with like bases, add together the exponents); and Quotient of Powers Law (when dividing powers with like bases, subtract the exponents).

Before watching this video, you should already be familiar with exponential notation.

After watching this video, you will be prepared to learn more about the Laws of Exponents and how they apply to both positive and negative exponents.

Common Core Standard(s) in focus: 8.EE.A.1 A video intended for math students in the 8th grade Recommended for students who are 13 - 14 years old

### TranscriptProduct and Quotient of Powers Laws

Archimedes is deep in thought in his seaside garden in ancient Greece. He's contemplating how many grains of sand it would take to fill the universe. While he's pondering, he notices a small child placing stones in a rectangular pattern. Eureka! The space filled with stones represents a small piece of the universe. Perhaps Archimedes can learn something here. Because the universe is exponentially large. Archimedes can use the Product and Quotient of Powers Laws to solve this mystery. Archimedes counts the stones in the pattern. The length of the first side is 8 stones. And the length of the second side is 16 stones. But what's that? For the first side, he hears the child counting two... times two... times two. And for the second side, two times two times two times two. The child is counting the stones by multiples of two! Like Archimedes, we already know that we can represent repeated multiplication with exponents. So, when we multiply 2 by itself three times, we can write that as 2 to the third power. And for the second side, 2 times itself 4 times equals 2 to the fourth power. How many stones would the child need to fill the entire rectangular area? To find out, we'd need to calculate the area by multiplying one side length by the other. That gives us 2 cubed times 2 to the fourth. To multiply powers with like bases lets first rewrite them in factored form. This means we have two times itself three times multiplied by two times itself four times. How many twos is that? We see that this expression is just 2 multiplied by itself 7 times. This can be written as 2 to the 7th power. Do you notice any relationship between the original exponents of 3 and 4 with the final exponent of 7? Well, adding together the exponents 3 and 4 gives us the sum of 7. Hmm, interesting. Archimedes decides to use this reasoning to further understand his grains of sand problem. He estimates the amount of sand in his rectangular garden to be 10 to the 5th times 10 to the 3rd. Again, let's write each term in factored form. Notice that we have 10 times itself 8 times. This can be written as 10 to the 8th power. What about the relationship between the original exponents of 5 and 3 with the final exponent of 8? Looks like when we multiply powers with the same base we can just add their exponents. This brings us to an important law of exponents called the Product of Powers law. Based on the patterns we've seen, we know that when we multiply powers with like bases, we can add together the exponents. This law holds true for all numbers and can help us simplify expressions of this case. But what happens when we divide like bases? Let's take a look at the fraction 3 to the fifth divided by 3 squared. To simplify this expression, we can write the numerator in factored form and the denominator in factored form. Remember, with fractions we can cancel out common factors. What are we left with? This results in 3 to the third power, also known as 3 cubed. Do you have a hypothesis about where that exponent of 3 came from? Well subtracting the exponents seems to give us the answer. Let's try one more example just to make sure. How about the expression 8 to the 6th power, divided by 8? Remember, any number can be written with an exponent of one, because it just means that number is there one time. Again, let's factor each term... then cancel out common factors. Does your hypothesis still hold true by subtracting the exponents? Yes, when we divide powers with like bases we subtract their exponents. This is called the Quotient of Powers law, and it's a close cousin to the Product of Powers law you just learned. It also works for all numbers except here we are dealing with fractions so 'x' cannot be zero. Let's review our findings. The product of powers law states when multiplying together powers with the same base you can add the exponents together to simplify the expression. While the quotient of powers law states when dividing powers with the same base you can subtract the exponents to simplify the expression. Remember that the base can't be zero in the quotient of powers law. With this knowledge Archimedes finds out that 10 to the 51st grains of sand fit in a sphere that would make up our universe. That's one, zero, zero, zero, zero, zero, zero, zero, zero, zero, zero,…

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1 comment
1. I like that math because it easy when I am 6 years old i like to do math i like it a lot

From Irdelmina Love , 9 months ago

## Product and Quotient of Powers Laws exercise

Would you like to apply the knowledge you’ve learned? You can review and practice it with the tasks for the video Product and Quotient of Powers Laws.
• ### Identify an equivalent expression using your understanding of the Product of Powers Law.

Hints

Make sure you remember to follow the Product of Powers Law. When multiplying powers with the same base, keep the base, and add the exponents.

When answering multiple choice questions, check each solution to make sure you are confident with your answer!

The expression $8^8$ is equivalent to $8^2\cdot8^6$.

Solution

$10^{25}\cdot10^{26}=10^{51}$

Since the bases are the same, the exponents can be added together to find the solution, which is 51

• ### Explain the Laws of Exponents pertaining to multiplication and division.

Hints

The Product of Powers Law states that if you have the same base and are finding a product, the base stays the same, and the exponents can be added.

The Quotient of Powers Law states that if you have the same base and are finding a quotient, the base stays the same, and the exponents can be subtracted.

Solution

The law called Products of Powers states that when multiplying exponents that have the same base, the base will stay the same, and then add the exponents.

For example, $(x^6)\cdot(x^2)$ has the same base of $x$. We can add the exponents, $\bf{6+2}$ to find that our exponent will now be $\mathbf{8}$.

$(x^6)\cdot(x^2)$ = $\bf{x^8}$

The law called Quotient of Powers states that when dividing exponents that have the same base, the base will stay the same, and then subtract the exponents.

For example, $\dfrac{x^6}{x^2}$ has the same base of $x$. We can subtract the exponents, $6-2$ to find that our exponent will now be $\bf{4}$.

$\dfrac{x^6}{x^2}$ = $\bf{x^4}$

• ### Interpret expressions written in exponential notation while applying the laws of exponents.

Hints

Rewriting exponential notation in factored form can help us understand the Product of Powers law.

$(y^2) \cdot (y^4) = (y \cdot y) \cdot (y \cdot y \cdot y \cdot y)$

Notice, that when the expression is factored, or expanded, there are a total of six $y$ s.

Rewriting exponential notation in factored form can help us understand the Quotient of Powers law.

$\dfrac{y^4}{y^2} = \dfrac{y \cdot y \cdot y \cdot y}{y \cdot y}$

Notice, that when the expression is factored, or expanded, there are a total of four $y$ s in the numerator and two $y$ s in the denominator.

Solution

The following expressions are equal to $2^4$:

$(2^2)\cdot(2^2)$

$(2^0)\cdot(2^4)$

$\frac{2^8}{2^4}$

$(2\cdot2\cdot2)\cdot(2)$

The following expressions are equal to $2^5$:

$(2^3)\cdot(2^2)$

$(2^4)\cdot(2^1)$

$\frac{2^9}{2^4}$

$(2\cdot2\cdot2)\cdot(2\cdot2)$

• ### Apply the Laws of Exponents to simplify the expressions.

Hints

Remember, when you are multiplying powers with like bases, keep the base, and add the exponents together.

$(w^2)\cdot(w^3) = w^{(2+3)} = w^5$

Remember, when you are dividing powers with like bases, keep the base, and subtract the exponents.

$\frac{d^7}{d^3} = d^{(7-3)} = d^4$

Solution

$(m^6)\cdot(m^7) = m^{13}$

$(m)\cdot(m^3) = m^4$

$(m^2)\cdot(m^7) = m^9$

$\dfrac{m^7}{m^2} = m^5$

$\dfrac{m^9}{m^6} = m^3$

$\dfrac{m^7}{m^6} = m$

• ### Simplifying expressions in exponential notation using the Product of Powers Law.

Hints

The Product of Powers Law states that when multiplying powers with the same base, follow these steps:

1. Keep the base the same.

Here is an example on how to apply the Product of Powers Law.

$(g^3)\cdot(g^7)$

$g^{(3+7)}$

$g^{10}$

To find the product of powers, we can keep the base the same, $x$, and add our exponents together, $3+5$.

Solution

$(x^3)\cdot(x^5) = \bf{x^{8}}$

Keep the base $x$ and add the exponents $3+5$.

• ### Apply your knowledge of the Laws of Exponents to simplify expressions.

Hints

First, simplify each numerator and denominator separately.

Apply your knowledge of the Product of Powers Law.

$n^6\cdot n^2=n^{6+2}=n^8$

If it helps you visualize better, expand (or write in factored form) both the numerator and the denominator.

Expanding looks like this:

$n^6\cdot n^2 = (n\cdot n\cdot n\cdot n\cdot n\cdot n) \cdot (n\cdot n)$

$\dfrac{(x)\cdot(x^5)}{(x^2)\cdot(x^3)}$

This can be expanded to look like this:

$\dfrac{(x)\cdot(x\cdot x\cdot x\cdot x\cdot x)}{(x\cdot x)\cdot(x\cdot x \cdot x)}$

Now the $x$'s can be canceled out.

$x^1=x$

Solution

$\dfrac{(n^2)\cdot(n^6)}{(n^3)\cdot(n)}$

$\dfrac{n^8}{n^4}$

$n^4$