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Graphing Linear Inequalities

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Basics on the topic Graphing Linear Inequalities

Writing Inequalities

In the world of mathematics, we often encounter situations where things are not exactly equal. This is where inequalities come in handy. They help us express when quantities are not equal but rather greater or lesser in value. For 6th graders, understanding inequalities is like adding a new tool to your math toolkit – one that is very important and widely used!

Writing Inequalities – Definition

Inequalities are mathematical statements that compare two values, showing that one value is greater than, less than, greater than or equal to, or less than or equal to another value. The symbols >, <, ≥, and ≤ represent these relationships.

Just like how a scale tilts to show which side is heavier, inequality symbols tell us which side has the greater number.

Symbol Common Words Example
> greater than 5 > 3 (5 is greater than 3)
< less than 2 < 4 (2 is less than 4)
greater than or equal to 7 ≥ 7 (7 is greater than or equal to 7)
less than or equal to 6 ≤ 9 (6 is less than or equal to 9)

Writing Inequalities – Example

Let’s look at the process for how to write an inequality, paying close attention to the properties of inequalities.

Identify the Relationship:

  • Determine whether the relationship between the items or quantities is about being "more than," "less than," "at least," or "no more than."

Choose the Right Symbol:

  • Use > for "greater than."
  • Use < for "less than."
  • Use for "greater than or equal to."
  • Use for "less than or equal to."

Set Up the Inequality:

  • Place the variable on one side of the inequality.
  • Place the known quantity or limit on the other side.

Examples:

Your friend has at least 3 pages left to read in a book.

  • This suggests your friend could have 3 or more pages left.
  • Write the Inequality: $ x \geq 3 $ (where $ x $ is the number of pages left)

You need to be younger than 18 to qualify for a youth discount.

  • The age must be less than 18.
  • Write the Inequality: $ y < 18 $ (where $ y $ is the age)

A plant grows more than 2 inches every month.

  • The growth per month is more than 2 inches.
  • Write the Inequality: $ g > 2 $ (where $ g $ is the growth per month in inches)

A container can hold no more than 750 milliliters of water.

  • The maximum capacity is 750 milliliters.
  • Write the Inequality: $ v \leq 750 $ (where $ v $ is the volume in milliliters)

Writing Inequalities – Practice

Write some inequalities to practice what you have learned.

Writing Inequalities – Summary

Key Learnings from this Text:

  • Inequalities help us compare numbers and express conditions where quantities are not equal.
  • The symbols >, <, ≥, and ≤ are used to represent different types of inequalities.
  • Inequalities can be manipulated by adding or subtracting the same amount from both sides, much like we do with equations.
  • They have practical applications in real life, such as budgeting money or managing time.

Explore more about inequalities and practice with interactive problems on our learning platform to strengthen your math skills!

Writing Inequalities – Frequently Asked Questions

What is an inequality in math?
What do the inequality symbols mean?
Can inequalities include variables?
How do you solve inequalities?
How can you show inequalities on a number line?
What happens to the inequality symbol when you multiply or divide by a negative number?
Can you have an inequality with more than one variable?
Are inequalities used in real life?
What's the difference between an inequality and an equation?
Is it possible for an inequality to have no solution?

Transcript Graphing Linear Inequalities

Lately, but possibly everyday, My Dear Aunt Sally has been so forgetful. For my birthday, she baked 15 cookies, trimming them with edible gold leaf, and she squeezed a bowl of lemons to make 10 glasses of lemonade, but then my mom reminded her that my birthday is not till next month.

Rather than toss the tasty treats, she decides to sell them. At the very least, she wants to recover the 50 dollars she spent on ingredients. So, how much should she charge for each treat? Let's help her.

Write a Linear Inequality in Slope-Intercept Form

Prior to evaluating My Dear Aunt Sally’s problem, let's write a linear inequality in slope-intercept form, then graph the inequality to determine the solution set.

What are the facts? Aunt Sally wants to sell 15 cookies and 10 glasses of lemonade. She needs to collect at least 50 dollars, so we should write the inequality using the greater than or equal to symbol.

The sum of 15 cookies for an unknown price, x, plus 10 glasses of lemonade for an unknown price, y, has to be greater than or equal to 50 dollars.

To put this in slope-intercept form, we have to move the terms around. First, using the opposite operation, move 15x to the other side of the inequality. Next, isolate the y by dividing both sides by ten.

Do we need to flip the inequality sign? No, since we're dividing by a positive number, we’re ok. Always remember to check the sign because if you multiply or divide by a negative number, you'll need to flip it.

Okay, where are we? Right, y ≥ −1.5x + 5. We're good to go!

Graphing a Linear Inequality in Slope-Intercept Form

Now that the inequality is in slope-intercept form, let’s graph it! The y-intercept is 5, and the slope is negative one point five. We know how to draw the line to indicate equal to but how do we represent greater than?

All the ordered pairs above the line will result in an answer that is greater than the equation we set up. Let’s shade this area.

To be certain this is correct, let’s check our work. Pick a point on the graph, any point. How about the ordered pair 1, 3? This point is below the line.

Will Aunt Sally collect 50 dollars or more if she sells 15 cookies for 1 dollar each and 10 glasses of lemonade for 3 dollars each? Do the math.

The product of 1 and 15 plus the product of 3 and 10 is equal to 45. No, this price plan won’t work and no wonder, the point 1, 3 is not in the area of values we shaded!

Any point along the line or in the shaded area will give Aunt Sally the pricing combo she needs to earn fifty dollars or more – that is, if she sells all of the tasty treats.

More Examples Graphs of Inequalities in Slope-Intercept Form

Now that you understand the concept, let’s look at some other inequalities and their graphs.

  • For y is less than or equal to x plus 2, notice the shaded area is below the solid line. All values on and below this line are in the solution set.
  • For y is greater than negative one-half x plus five, we use a dashed line as, the values on the line are not part of the solution set. Only the values above the dotted line solve the inequality.
  • For y is less than negative x plus 4, we have to use a dashed line; but this time, the values below the dashed line are in the solution set.

Let’s make a graphic organizer to help you remember.

  • For y is greater than or equal to, the line is solid, and the values on and above the line satisfy the inequality.
  • For y is less than or equal to, the line is solid, and the values on and below the line are part of the solution set.
  • For y is greater than, we must use a dashed line, and only the values above the line are part of the solution set and lastly, for y is less than, the line is dashed and only the values below the line satisfy the inequality.

Summary: Steps to Solve Linear Inequalities by Graphing

Let’s summarize the steps to solve inequalities:

  • Write your equation in slope-intercept form.
  • While isolating the variable, if needed, flip the inequality symbol.
  • Draw the appropriate line, solid or dashed.
  • Determine if the solution set includes the area above or below the line, then pick any point and check your work.

Predictably excited, My Dear Aunt Sally sold all of the cookies and all the glasses of lemonade! She’s ecstatic, but wait. You won’t believe this! It’s Aunt Sally’s birthday! How did she forget her own birthday?!

Graphing Linear Inequalities exercise

Would you like to apply the knowledge you’ve learned? You can review and practice it with the tasks for the video Graphing Linear Inequalities.
  • Decide which graph describes the given situation.

    Hints

    First, have a look at the line. Does the line correspond to the inequality $y=-1.5x+5$?

    For $\ge$ or $\le$ situations, the line is solid otherwise it needs to be dashed.

    • $\ge$ or $>$ will give us solutions above and
    • $\le$ or $<$ beyond the line.
    Solution

    The inequality

    $y\ge -1.5x+5$

    is written in slope-intercept form.

    To graph, draw the line of the equation $y=-1.5x+5$ on a coordinate grid :

    • this line passes the y axis at $y=5$ and
    • the slope is $m=-1.5$. So for each one step to the right we go 1.5 steps down.
    Because we have a greater than or equal to situation
    • the line is solid, and
    • the solutions lie above the solid line.
    So the graph on the right matches the inequality.

  • Determine which graph corresponds to which inequality.

    Hints

    First, take a look at the lines.

    Are the lines solid ($\le$ or $\ge$) or dashed ($<$ or $>$)?

    Solution

    Graphing linear inequalities:

    1. First, we draw the line corresponding to the equation $y=mx+b$.
    2. Next, we look at the inequality sign:
    • $\ge$ $\rightarrow$ solid line and the solutions lie above the line
    • $>$ $\rightarrow$ dashed line and the solutions lie above the line
    • $\le$ $\rightarrow$ solid line and the solutions lie beyond the line
    • $<$ $\rightarrow$ dashed line and the solutions lie beyond the line
    There are graphs that couldn't be matched up:
    • the violet one belongs to the equation $y=-1.5x+6$ which is not given and
    • the turquoise one belongs to the inequality $y<x+2$.
    These were the correct matches:
    1. The red graph belongs to the inequality $y\ge -1.5x+5$.
    2. The green graph belongs to the inequality $y\le x+2$.
    3. The blue graph belongs to the inequality $y> -\frac12x+5$.
    4. The orange graph belongs to the inequality $y<-x+4 $.

  • Decide which values would earn aunt Sally enough money.

    Hints

    $x$ is the price for one cookie, and $y$ represents the price for one glass of lemonade.

    Plug the prices into the inequality:

    $15\times x+10\times y\ge 50$

    and check if Aunt Sally met her goal.

    Remember that the inequality shown is greater than or equal to.

    Solution

    Each combination of the prices for the cookies and lemonade can be drawn as a point on the coordinate graph. Just have a look at the picture on the right.

    The price for one cookie is represented by $x$, and the price for one glass of lemonade is represented by $y$. Therefore, you have to look at the x and y axis to find a suitable combination.

    $\mathbf{x=2,~y=2}$. You can see this point is plotted on the line:

    $15\times 2+10\times 2=30+20=50$. Aunt Sally needs to earn $50, so she is satisfied with her earnings.

    $\mathbf{x=1.2,~y=2.5}$. This point below the line. Therefore, it doesn't meet aunt Sally's goal of earning at least $\$50$. $15\times 1.2+10\times 2.5=18+25=43<50$.

    $\mathbf{x=3,~y=1.5}$. You can see this point lies above the line:

    $15\times 3+10\times 1.5=45+15=60$. This is more than the $\$50$ Aunt Sally had hoped to earn. She will be very satisfied with her earnings.

  • Decide which graph corresponds to the given inequality.

    Hints

    First, write the inequality.

    You'll get: $12\times x+10\times y\ge 30$.

    Rewrite this inequality into an equation in slope-intercept form.

    The equation describing the line is:

    $y=-1.2x+3$.

    Solution

    Let's have a look at the inequality :

    $12\times x+10\times y\ge 30$.

    We rewrite this inequality as an equation in slope-intercept form: $\begin{array}{rcl} 12 x+10 y&\ge& 30\\ \color{#669900}{-12x} && \color{#669900}{-12x}\\ 10y&\ge&-12x+30. \end{array}$

    Now we divide by $10$: $y\ge -1.2x+3$.

    We draw theline corresponding to $y=-1.2x+3$.

    • Because of the $\ge$ sign this line is solid and
    • because of greater or equal to sign the solutions lie above this line.
    The correct graph can be seen on the right.

  • Summarize how you can recognize the solution depending on the inequality sign.

    Hints

    If the points on the line are also solutions, you can recognize this by a solid line otherwise a dashed line.

    If the points on the line are also solutions, the corresponding inequality sign is $\ge$ or $\le$.

    Greater corresponds to above the line.

    Solution

    Just remember the solutions depending on the relation sign:

    • $\ge$ $\rightarrow$ solid line and the solutions lie above the line.
    • $\le$ $\rightarrow$ solid line and the solutions lie beyond the line.
    • $>$ $\rightarrow$ dashed line and the solutions lie above the line.
    • $<$ $\rightarrow$ dashed line and the solutions lie beyond the line.
    Or:
    • Greater than or less than as well as equal $\rightarrow$ solid line and dashed line otherwise.
    • Greater than or greater than or equal to $\rightarrow$ above the line and beyond otherwise.
  • Decide if the given points lie within the area described by the inequalities.

    Hints

    Draw the lines corresponding to $y=x+3$ and $y=x+1$ into a coordinate system.

    Hint: these lines are parallel.

    There's no point that's a solution to both inequalities.

    Pay attention to the different signs of the inequalities.

    Solution

    The shaded areas of the graph on the right shows the solution for two inequalties.

    The solid red line belongs to the equation $y=x+1$, the dashed one corresponds to $y=x+3$. These lines are parallel.

    The solutions of $y\le x+1$ lie in the red area, and those of $y>x+3$ in the green area. Remember that the points on the green line don't belong to the solution set.

    So the point on the green line as well as both points between the two lines don't belong to either inequality.

    The point $(0.5,4.5)$ are a solution to the inequality $y>x+3$.

    All the other points, including $(1,2)$ lying on the red line, are solutions to the inequality $y\le x+1$.