Multiplying Special Case Polynomials 06:00 minutes
Transcript Multiplying Special Case Polynomials
GSquared and FoxyCooke are competing hackers. They're always trying to best each other. This time, they're trying to hack into a company’s security system. Whoever gets into the system first will be the winner of eternal fame and glory. GSquared is at the first security wall. To gain access to the first level, he has to simplify this expression, the sum of 'a' and 'b' squared, AKA the sum of 'a' and 'b' times the sum of 'a' and 'b'.
The binomials
GSquared knows a good strategy when he sees one. He uses an area model to find the product of the two binomials.To set up the area model, he divides a rectangle into 2 rows and 2 columns and labels each of the 4 sections with a term from the 2 binomials. Then he calculates the area of each section and writes it down in the corresponding section of the area model.
(a)(a) = a²,
(a)(b) = ab,
(b)(a) = ab,
(b)(b) = b².
Calculate the product of two binomials
He adds the four terms together, groups the like terms and finally, writes the expression in the standard form. The result? a² + 2ab + b². He knows he's got this, so he enters the password…Gosh darn it. That FoxyCooke got here first. GSquared was too slow. Does Foxy know a faster way to calculate the product of two binomials? She does know a faster way…
Simplify the expression
When Foxy saw the expression, she immediately recognized the pattern. She knows the square of a binomial sum is equal to a perfect square trinomial! GSquared reaches the wall of the 2nd level. Hoping to be faster than last time, he tries a different method to simplify the expression. He uses the FOIL method to simplify the difference of a and b times the difference of a and b.
The FOIL method
FOIL stands for first, outside, inside, and last. This is a mnemonic device used to simplify the product of two binomials. Let's try it out, but we have to go fast! First, multiply the first two terms, (a)(a) = a². Next, multiply the outer terms, (a)(b) = ab. Now the inside terms, (b)(a). The product is 'ab'. Last, the last terms, (b)(b) = b².
The perfect square trinomial
Combine the like terms and... the simplified expression is a²  2ab + b². He enters the password and...Although he used the FOIL method, he's foiled again by Foxy – she beat him a second time. How did she do it? Again Foxy recognized a pattern. This expression is the square of a binomial difference and she used another perfect square trinomial to crack the password in just seconds.
Multiplication problem
Finally the last wall... This time the task is a multiplication problem, 42 times 38. GSquared is a pro at multiplication, so he's not worried... Are you kidding me? That Foxy is a real fast fox. Look how she used the difference of two squares to solve the problem fast like lightning. When you have the expression of the sum of a and b times the difference of a and b, watch what happens when you apply the FOIL method the inner and outer products cancel each other out to leave the difference of two squares!
The DOTS expression
This is also known as a DOTS expression That Foxy, she applied DOTS to the number 42 and 38 rewriting them as 40 plus 2 and 40 minus to get a difference of two squares, then she simplified the exponents and calculated the difference to equal 1,596! She recognized the pattern of a difference of two squares!
Pay attention and you'll start to notice these patterned expressions too, just like Foxy. This summary Foxy used is super helpful to help you learn to recognize the polynomial patterns, so you can save time and be Foxyfast. Foxy's the clear winner, for sure , but hold on... What’s going on here? It looks as though our two hackers got hacked…by their mom! It`s time for dinner.
Multiplying Special Case Polynomials Exercise
Would you like to practice what you’ve just learned? Practice problems for this video Multiplying Special Case Polynomials help you practice and recap your knowledge.

Calculate the term ${(a+b)^2}$.
Hints
Imagine you cut the square with side lengths ${a+b}$ into two squares and two rectangles.
The area of the original square is the same as the sum of the two smaller squares and two rectangles.
You can also use the FOIL method to simplify ${(a+b)(a+b)}$.
Solution
The expression ${(a+b)(a+b)}$, or ${ (a + b)^2}$, can be simplified using the area model.
Imagine a square with side lengths ${a+b}$; its area is ${(a+b)^2}$.
You can divide this square into two smaller squares with sides $ a$ and $b$, respectively, as well as two rectangles with a height $a$ and length $b$.
The areas of the squares are ${a^2}$ and ${b^2}$, while each rectangle has an area equal to ${ ab}$.
Combining the like terms gives us ${(a+b)^2=a^2+2ab+b^2}$.

Summarize the multiplication of special binomials.
Hints
The difference of two squares is ${(a+b)(ab)}$.
You can simplify the expansion of binomials by using the FOIL method.
For ${ (a+b)(a+b)}$, use the FOIL method:
F multiply the first ${a \times a}$
O multiply the outer ${a \times b}$
I multiply the inner ${b \times a}$
L multiply the last ${b \times b}$
Solution
How can you remember the pattern for multiplying of binomials?
Perfect Square Binomials
${ \begin{array}{rcl} (a + b)(a + b) &=&\\ &=& a^2 + ab + ab + b^2\\ &=& a^2 + 2ab + b^2 \end{array}}$
$~$
${\begin{array}{rcl} (a  b)(a  b) &=&\\ &=& a^2  ab  ab + b^2\\ &=& a^2  2ab + b^2 \end{array}}$
Difference of Two Squares
${\begin{array}{rcl} (a + b)(a  b) &=&\\ &=& a^2  ab + ab + b^2\\ &=& a^2b^2 \end{array}}$

Use the area model to simplify the expression.
Hints
${ \begin{array}{rcl} (4y)^2 &=&\\ 4^2 \times y^2 &=& 16y^2 \end{array}}$
Draw the square and write the areas in the corresponding squares or rectangles.
Solution
If you have a perfect square binomial such as $(x + a)^2$, you can approach this in two ways:
1.$~$Using FOIL
${\begin{array}{rcl} (x + a)^2 &=&\\ &=& (x + a)(x + a)\\ &=& x^2 + ax + ax + a^2\\ &=& x^2 + 2ax + a^2\\ ~\\ \end{array}}$
2.$~$Using the FOIL shortcut for Perfect Square Binomials
${ \begin{array}{rcl} ~\\ (x + a)^2 &=&\\ &=& x^2 + 2(ax) + a^2\\ \end{array}}$
$~$
${ \begin{array}{rcl} (x + 5)^2&=&\\ &=& x^2 + 2 \times 5x + 5^2\\ &=& x^2 + 10x + 25 \end{array}}$
$~$
${ \begin{array}{rcl} (3 + 3x)^2&=&\\ &=&3^2 + 2 \times 3 \times 3x + (3x)^2\\ &=& 9x^2 + 18x + 9 \end{array}}$
$~$
${ \begin{array}{rcl} (1 + 4y)^2&=&\\ &=&1^2 + 2 \times 1 \times 4y + (4y)^2\\ &=& 16y^2 + 8y + 1 \end{array}}$
$~$
${ \begin{array}{rcl} (2x + 4)^2&=&\\ &=&(2x)^2 + 2 \times 2x \times 4 + 4^2\\ &=& 4x^2+16x+16 \end{array}}$

Explain the FOIL method to Jack.
Hints
Here you see an example for $(2x+4)^2$ using the area model. This corresponds to the FOIL method.
$(2x + 4)^2 = (2x)^2 + 2x(4) + 4(2x) + 4^2$
Remember, you have to apply the exponent to every term in the parentheses.
${ \begin{array}{rcl} (3y)^2 &=&\\ &=& 3y(3y)\\ &=& 9y^2 \end{array}}$
Look at this example for the FOIL method:
${ \begin{array}{rcl} (2a  b) &=&\\ &=& 2a(2a) + 2a(b) + b(2a) + b(b)\\ &=& (2a)^2  4ab + b^2 \end{array}}$
Solution
We can expand the given perfect square binomial, $(5x2y)^2$, using the FOIL method. First, we transform the expression:
${ (5x2y)^2=(5x2y)(5x2y)}$
$~$
Let's start.
F multiply the first ${\large 5x(5x) = 25x^2}$
O multiply the outer ${\large 5x(2y) = 10xy}$
I multiply the inner ${\large 2y(5x) = 10xy}$
L multiply the last ${\large 2y(2y) = 4y^2}$
$~$
We still have to combine like terms.
${(5x  2y)^2 = 25x^2  20xy + 4y^2}$
Party on, Jack!

Explain the FOIL method.
Hints
You can use the distributive property for ${ a(ab)=a^2ab}$ and for ${ b(ab)=ab+b^2}$.
Here is another example.
Solution
We can simplify ${ (a  b)^2 = (a  b)(a  b)}$ using FOIL multiplication.
For ${ (a + b)(a + b)}$, use the FOIL method:
F multiply the first ${ a \times a}$
O multiply the outer ${ a \times b}$
I multiply the inner ${ b \times a}$
L multiply the last ${ b \times b}$
For the final step, we add all the resulting terms:
${ a^2  ab  ab + b^2 = a^2  2ab + b^2}$

Simplify the following expressions.
Hints
Use the formulas above and think about what to assign to $a$ as well as to $b$.
For example: $(2x4)$.
You use the second formula with $a = 2x$ and b = 4$.
You can use those formulas also for calculating products of numbers
${ 22 \times 18 = (20 + 2)(20  2)}$.
Now we can plug in ${ a = 20}$ and ${ b = 2}$ in our third formula.
${ \begin{array}{rcl} 22 \times 18 &=& (a + b)(a  b)\\ &=& a^2  b^2\\ &=& 20^2  2^2\\ &=& 400  4\\ &=& 396 \end{array}}$
Solution
These formulas show a pattern to simplify the multiplication of special binomials.
Now, we'd like to practice using these formulas by substituting ${a}$ and ${ b}$ in the expressions:
First expression: $(12  3z)^2$
When ${ a = 12}$ and ${ b = 3z}$, we can use the second equation, ${(a + b)^2}$.${ \begin{array}{rcl} (12  3z)^2 &=&\\ &=& 12^2  2(12)(3z) + (3z)^2\\ &=& 144  72z + 9z^2 \end{array}}$
$~$
Second expression: $96 \times 104$
We should recognize that we can use the third formula:${ \begin{array}{rcl} 96 \times 104 &=& (a + b)(a  b) \end{array}}$
Substituting $a = 100$ and $b = 4$, we get:
${ \begin{array}{rcl} &=& (100  4)(100 + 4)\\ &=& (100 + 4)(100  4)\\ &=& 100^2  4^2\\ &=& 10000  16\\ &=& 9984 \end{array}}$
$~$
Third expression: $(1 + 9z)^2$
Using the second formula with $a = 1$ and $b = 9z$, we get:${ \begin{array}{rcl} (1 + 9z)^2 &=&\\ &=& 1^2 + 2(1)(9z) + (9z)^2\\ &=& 1 + 18z + 81z^2 \end{array}}$
$~$
Fourth expression: $(3z  4)^2$
Given the expression $(3y  4)^2$, we can use the first formula, but we have to remember to pay attention to the signs.Using $a = 3y$ and $b = 4$, we get:
${ \begin{array}{rcl} (3z  4)^2 &=&\\ &=& (3z)^2 + 2(3z)(4) + (4)^2\\ &=& 9z^2  24z + 16 \end{array}}$