**Video Transcript**

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Transcript
**Distance - Rate - Time – Different Directions**

Tim Carcrashian, true to his name, works for a vehicle crash testing company. His job is to set up the **slow-motion-camera** used to document car crashes. The set-up of the camera is very expensive and time-consuming. To do the job just right, Tim needs to know exactly when and where the cars will crash. How can we help him?

### The distance-rate-time pyramid

This is a distance-rate-time problem - with cars coming from different directions. For the test crash, Car 1 and Car 2 will drive towards each other. Car 1 will pass Point A going 50 miles per hour, and Car 2 will pass Point B going 70 miles per hour. The **distance** from Point A to Point B is 1.2 miles.

Exactly where and when will the cars crash? Let’s figure out how to **solve** this **problem**. Distance is equal to rate times time. This pyramid can help us remember the formula. A shorter, more common, way to say this d = rt.

### Write equations

Ok, let's get started...It's a good idea to use a table to **organize** the data. First, let's fill in the values with what we already know, the rate for each car. We don’t know the value for time yet, just that it's the same for both cars, so for now, we can represent this with the **variable**, 't'. We can write two **equations** to describe what's going on here: d = 50t. And...d = 70t.

Let's write that information into the table. Since we know the total distance the two cars will a travel together is 1.2 miles, we can set up an equation and solve for the unknown **time**. 1.2 = 50t + 70t. Evaluating this we get: t = 1/100 of an **hour**. Let's fill in the table... Now, we can use the value we just calculated for the time to **determine** the actual distances both cars will drive before crashing and fill in the table.

d = 50(0.01), which is equal to 0.5

d = 70(0.01), giving us 0.7

### The distance-rate-time formula

This is just great! Tim is so happy! Using the **distance-rate-time formula**, coming from different directions, now, Tim knows Car 1 will drive exactly 1/2 of a mile and Car 2 will drive 7/10 of a mile, then crash, bang, boom! As a bonus, Tim also knows exactly when this will happen. The cars will crash after 36 seconds, which is equal to 1/100 of an hour. He sets up the Slow-Motion-Camera Unit just right. He’s so good at his job, maybe he'll get a promotion and a big raise!

Oh no. One week later, Tim learns the test track will be under construction in order to improve the testing **conditions**. During construction, the right side of the track will be shortened. Instead of the track having a distance of 1/2 of a mile on the left side and 7/10 of a mile on the right side...

### Calculate a new rate

The right side will be only 4/10 of a mile long. Tim doesn't want to change the set-up of the camera. What can he do so the cars will still crash at the same **place** and time? He can't change the distance or the time, but he can change the speed of Car 2. Let's calculate the new rate using the distance-rate time formula.

As before, we have d = rt. To **isolate** the rate, divide distance by time. r = 0.4 / 0.01. The rate is 40 miles per hour. So, if Car 2 travels on the track at a rate of 40 miles per hour for 4/10 of a mile, after 1/100 of an hour, the two cars will **crash** in just the right spot.

### Change the distance

Another week goes by... Tim gets an email... The track improvements are all done, and the new plan is to crash test one of the cars driving at a very high **speed**. Car 2 will be tested driving 90 miles per hour. Tim doesn't have time to change the camera. What should he do? He can't change the speed or the time, but he can change the distance Car 2 will **drive**.

If Car 2 drives 90 miles per hour for 1/100 of an hour, use the distance-rate-time formula to calculate the new distance it must drive so the camera can capture the crash. Let's reuse our **formula** from before: distance is equal to rate times time. 90(0.01) = 0.9 miles. So Tim can get the perfect camera shot, Car 2 must drive 9/10 of a mile at 90 miles per hour for 1/100 of an hour .

### Summary

Let's **summarize**: The distance-rate-time pyramid is a handy **graphic** organizer to help you remember and understand how to solve these kind of problems. **t = d/r, r = d/t, d = rt**. After all his hard work, Tim can finally watch the crash test. Oh no, that's not test Car 2...That looks a lot like Tim's boss' car...

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