Using Place Value to Add Two Digit Numbers (Regrouping) — Let's Practice!
Basics on the topic Using Place Value to Add Two Digit Numbers (Regrouping) — Let's Practice!
Using Place Value to Add TwoDigit Numbers (Regrouping) – Introduction
We're diving into the world of using place value to add twodigit numbers. This method helps us understand the value of each digit in a number and how to regroup when necessary. Get ready because today, we're going to practice this together!
What Is Place Value Addition?
Place value addition involves adding numbers based on the value of each digit, starting with the tens place and then the ones place. If the ones add up to ten or more, we regroup by carrying over to the tens place.
Here are the steps to tackle addition using place value:
Step #  Action 

1  Read the problem and determine what you are asked to find. 
2  Add the ones place digits together. 
3  Add the tens place digits together. 
4  If the ones add up to ten or more, regroup by carrying over to the tens place. 
5  Combine the sums of the tens and ones places. 
6  Check your answer to ensure it makes sense with the problem. 
Let's practice understanding place value addition with a few examples.
Solving Place Value Addition Problems – Example
Example 1:
What is 25 + 38?
Steps to Solve the Problem:
Step #  Action  Pictorial Representation 

1  Add the ones place digits: 5 + 8 = 13 (regroup)  
2  Regroup: 13 ones = 1 ten and 3 ones  
3  Add the tens place digits: 2 + 3 = 5  
4  Add the carriedover ten to the tens place: 5 + 1 = 6  
5  Combine: 60 + 3 = 63 
The sum is 63.
Example 2:
What is 36 + 34?
Steps to Solve the Problem:
Step #  Action 

1  Add the ones place digits: 6 + 4 = 10 (regroup) 
2  Regroup: 10 ones = 1 ten and 0 ones 
3  Add the tens place digits: 3 + 3 = 6 
4  Add the carriedover ten to the tens place: 6 + 1 = 7 
5  Combine: 70 + 0 = 70 
The sum is 70.
Example 3:
What is 46 + 37?
Steps to Solve the Problem:
Step #  Action 

1  Add the ones place digits: 6 + 7 = 13 (regroup) 
2  Regroup: 13 ones = 1 ten and 3 ones 
3  Add the tens place digits: 4 + 3 = 7 
4  Add the carriedover ten to the tens place: 7 + 1 = 8 
5  Combine: 80 + 3 = 83 
The sum is 83.
Solving Place Value Addition Problems – Practice
Now, let's put your skills to the test. Solve these problems on your own, and check the solutions when you're ready!
Solving Place Value Addition Problems – Summary
Key Learnings from this Text:
 Solving problems using place value can be achieved by following these steps:
 Step #  Action   1  Read the problem and determine what you are asked to find.   2  Add the ones place digits together.   3  Add the tens place digits together.   4  If the ones add up to ten or more, regroup by carrying over to the tens place.   5  Combine the sums of the tens and ones places.   6  Check your answer to ensure it makes sense with the problem. 
 Mastering place value addition is an important foundational math skill.
Keep practicing these steps, and you'll become a pro at adding numbers using place value! Check out more fun math challenges and exercises on our website to continue sharpening your skills.
Solving Place Value Addition Problems – Frequently Asked Questions
Transcript Using Place Value to Add Two Digit Numbers (Regrouping) — Let's Practice!
Razzi says get these items ready (...) Because today we're going to practice... Using Place Value to Add Two Digit Numbers (Regrouping) It's time to begin! Remember that there are many strategies to add, like using place value. Place value is the value of each digit depending on where it is in the number. Let's use base ten blocks to add and regroup with place value. What is twentyfive plus thirtyeight? You can add the tens rods together first, then the ones blocks. Then, if you have enough ones to make a ten, regroup and add it to the tens place. Did you also get sixtythree? Let's tackle the next problem! What is thirtysix plus thirtyfour? You can add the tens rods together first, then the ones blocks. Then, if you have enough ones to make a ten, regroup and add it to the tens place. Did you also get seventy? Let's tackle the final problem! What is fortysix plus thirtyseven? You can add the tens rods together first, then the ones blocks. Then, if you have enough ones to make a ten, regroup and add it to the tens place. Did you also get eightythree? Razzi had so much fun practicing with you today! See you next time!
Using Place Value to Add Two Digit Numbers (Regrouping) — Let's Practice! exercise

Find the sum.
HintsHow many blue tens rods will there be at first? 2 + 3 = 5.
How many green ones blocks will there be at first? 6 + 5 = 11.
We have enough ones to make a ten, so we regroup and add them to the tens place on the left.
We add the tens rods together and the ones blocks together to calculate the sum.
Solution 2 is in the tens place of 26, so we draw 2 blue tens rods in the first row. 6 is in the ones place, so we draw 6 green ones blocks.
 3 is in the tens place of 35, so we draw 3 blue tens rods in the second row. 5 is in the ones place, so we draw 5 green ones blocks.
 We have enough ones in the second row to make a ten, so we regroup and add them to the tens place on the left.
 For the tens rods: 2 + 3 + 1 = 6. 6 is the number in the tens place of the sum.
 For the ones blocks: there is only 1 left. 1 is the number in the ones place of the sum.

Find each sum.
HintsFirst, add the tens rods.
For example, 29 + 27 has 2 + 2 = 4 tens rods.
Then, add the ones blocks.
29 + 27 has 9 + 7 = 16 ones blocks.
We have enough ones to make a ten, so we regroup and add them to the tens place on the left.
We add the tens rods together (2 + 2 + 1) and the ones blocks together (4 + 2) to calculate the sum.
SolutionTo solve 29 + 27:
 2 is in the tens place of 29, so we draw 2 blue tens rods in the first row. 9 is in the ones place, so we draw 9 green ones blocks.
 2 is in the tens place of 27, so we draw 2 blue tens rods in the second row. 7 is in the ones place, so we draw 7 green ones blocks.
 We have enough ones in the second row to make a ten, so we regroup and add them to the tens place on the left.
 For the tens rods: 2 + 2 + 1 = 5. 5 is the number in the tens place of the sum.
 For the ones blocks: 4 + 2 = 6. 6 is the number in the ones place of the sum.
The other answers are:
* 23 + 17 = 40
* 45 + 28 = 73

Find each sum.
HintsFirst, add the tens rods.
For example, 18 + 49 has 1 + 4 = 5 tens rods.
Then, add the ones blocks.
For example, 18 + 49 has 8 + 9 = 17 ones blocks.
We have enough ones to make a ten, so we regroup and add them to the tens place on the left.
We add the tens rods together (1 + 4 + 1) and the ones blocks together (3 + 4) to calculate the sum.
SolutionThe correct answers are:
 18 + 49 = 67
 15 + 17 = 32
 27 + 23 = 50
 42 + 38 = 80
 1 is in the tens place of 18, so we draw 1 blue tens rod in the first row. 8 is in the ones place, so we draw 8 green ones blocks.
 4 is in the tens place of 49, so we draw 4 blue tens rods in the second row. 9 is in the ones place, so we draw 9 green ones blocks.
 We have enough ones in the second row to make a ten, so we regroup and add them to the tens place on the left.
 For the tens rods: 1 + 4 + 1 = 6. 6 is the number in the tens place of the sum.
 For the ones blocks: 3 + 4 = 7. 7 is the number in the ones place of the sum.

Solve the addition problem.
HintsIn order to find how many total guests Razzi needs to invite, we add the number of friends and the number of family members.
Razzi has 16 friends and 55 family members.
Therefore, we add 16 + 55.
16 + 55 has 6 tens rods and 11 ones blocks.
We have enough ones to make a ten, so we regroup and add them to the tens place on the left.
SolutionIn order to find how many total guests Razzi needs to invite, we add the number of friends and the number of family members. Razzi has 16 friends and 55 family members. Therefore, we add 16 + 55.
 16 + 55 has 6 tens rods and 11 ones blocks.
 We have enough ones to make a ten, so we regroup and add them to the tens place on the left.
 For the tens rods: 1 + 5 + 1 = 7. 7 is the number in the tens place of the sum.
 For the ones blocks: there is only 1 left. 1 is the number in the ones place of the sum.
Razzi needs to invite 71 guests to his party.

Complete the addition problem.
HintsHow many blue tens rods will there be at first? 2 + 1 = 3.
How many green ones blocks will there be at first? 9 + 5 = 14.
We have enough ones to make a ten, so we regroup and add them to the tens place on the left.
We add the tens rods together and the ones blocks together to calculate the sum.
Solution 2 is in the tens place of 29, so we draw 2 blue tens rods in the first row. 9 is in the ones place, so we draw 9 green ones blocks.
 1 is in the tens place of 15, so we draw 1 blue tens rod in the second row. 5 is in the ones place, so we draw 5 green ones blocks.
 We have enough ones in the second row to make a ten, so we regroup and add them to the tens place on the left.
 For the tens rods: 2 + 1 + 1 = 4. 4 is the number in the tens place of the sum.
 For the ones blocks: there are 4 left. 4 is the number in the ones place of the sum.

Complete each addition problem.
HintsFor 79 + ___ = 93:
To get a 3 in the ones place of the sum, we need to find a number that when added to the 9 in the ones place of 79 makes 13.
9 + 4 = 13. Therefore, 4 is in the ones place of our answer.
To solve 81 + 29, we follow the same process from the video.
How many tens rods will there be? How many ones blocks will there be?
SolutionTo solve 79 + ___ = 93:
 We need to find the number that we add to 79 to get 93. (see image)
 To get a 3 in the ones place of the sum, we need to find a number that when added to the 9 in the ones place of 79 makes 13.
 9 + 4 = 13. Therefore, 4 is in the ones place of our answer.
 79 + 14 = 93. The answer is 14.
To solve ___ + 23 = 81:
 We need to find the number that we add to 23 to get 81.
 To get a 1 in the ones place of the sum, we need to find a number that when added to the 3 in the ones place of 23 makes 11.
 8 + 3 = 11. Therefore, 8 is in the ones place of our answer.
 58 + 23 = 81. The answer is 58.
To solve 81 + 29 = ___:
 We are finding the sum, so we follow the same process from the video.
 We have 10 tens rods and 10 ones blocks.
 We have enough ones to make a ten, so we regroup and add them to the tens place on the left. There are now 0 ones blocks on the right.
 Finally, we add the tens rods together and the ones blocks together to calculate the sum.
 81 + 29 = 110. The answer is 110.
Addition Using Expanded Form
Using Place Value to Add
Addition with Regrouping  Ten
Three Digit Addition with Regrouping  Expanded Form
Adding 2 Digit Numbers Using Standard Algorithm
Adding 3 Digit Numbers Using Standard Algorithm
Using Place Value to Add Two Digit Numbers (Regrouping) — Let's Practice!
Using Place Value to Subtract (Regrouping)
Using Place Value to Add Two Digit Numbers (No Regouping)