The Pythagorean Theorem
Description The Pythagorean Theorem
The Pythagorean Theorem is an important result which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of its other two sides; i.e. a2 + b2 = c2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.
Pythagorean triples are triples (a,b,c) of numbers which satisfy the Pythagorean Theorem. Given three numbers, the Pythagorean Theorem can be used to see if it is possible for those numbers to make up the side lengths of a right triangle or not.
The Pythagorean Theorem can also be used to solve various problems involving right triangles, like finding the length of a ladder leaning on a wall given the height of the wall and the distance of the foot of the ladder to the base of that wall.
Understand and apply the Pythagorean Theorem.
CCSS.MATH.CONTENT.8.G.B.6
Transcript The Pythagorean Theorem
Damo, the son of Pythagoras, wants to build a vacation cottage for his mother and father. In keeping with the family business of triangles, Damo decides to incorporate the shape into the design of the cottage. What a perfect time to use his dad's theorem:The Pythagorean Theorem!
Right Triangles and Pythagorean Triples
For the roof of the cottage, Damo will use a triangle design, but what size and shape should the triangle be? Damo's dad spoke of many combinations of integers to create the three sides of right triangles, called Pythagorean triples, but which one is best? Damo thinks back to his dad's class on triangles from school. His dad taught him well! He remembers that right triangles have one and only one right angle, and a right angle is equal to 90°. Even though one angle has to be 90°, there are several different combinations of side lengths that Damo can use.
These special relationships are called Pythagorean Triples. If the integer side lengths of a triangle create a Pythagorean triple, the formula a² + b² = c² will work. How about this triangle, is it a Pythagorean triple? Let's see. The triangle has a right angle, and if you sum the area of the two smaller squares, the sum is equal to the area of the larger square.
Examples for Pythagorean Triples
Damo has a choice of several different roof shapes, but he wants one in the shape of a right triangle, and it must be just right for the cottage.
The first Pythagorean triple Damo remembers is 345. Plugging this into dear ol' dad's theorem gives him, 3² + 4² = 5² ...which is 9 + 16 = 25. This is awesome! No wonder dad gets so excited about right triangles. He knows this one is in the shape of a right triangle, but it's too small.
Next, he tries side lengths 8, 15, and 17. Let’s see, is it a right triangle? Shall we try out the theorem? 8² + 15² = 17². So...64 + 225 = 289. Yup, this one works too, but darn – it looks just like the roof on top of Yorgos’ Yogurt Shop, and that just won’t do for his parents.
There are only a few more roof styles that the roof cutters offer: Damo checks the larger roof, with side measures 72425, first. Does it satisfy the theorem? 7² + 24² = 25². This is the same as 49 + 576 = 625. Yes it works, but it’s just too big.
There's one last option, a triangle with side lengths of 5, 12 and 13. I sure hope this one works 25 + 144 = 169. Yeah! This shape is a right triangle, and it's just the right size and style. So Damo picked a roof that's just right. He also practiced the Pythagorean Theorem and learned some Pythagorean triples. Seems like a win, win to me!
The roof of the cottage looks great, and his dad looks very pleased with the shape. Oh no! Damos forgot that different materials have different densities. Oh Geez. Where was Damo when his dad was teaching the unit on density?? I guess he can still learn something from his dear ol' dad. Join us next time for more triangular adventures with Damo!
The Pythagorean Theorem Exercise

Define the Pythagorean Theorem.
HintsThe Pythagorean theorem focuses on the side lengths of right triangles.
The Pythagorean Theorem focuses on the relationships between the side lengths of right triangles.
Some options in the answer set are true statements about triangles, but are not part of the Pythagorean Theorem.
SolutionThe Pythagorean Theorem relates the side lengths of right triangles. The theorem states that the side lengths of right triangles have a special relationship with each other that is described by the equation $a^2 + b^2 = c^2$. Further, there are sets of integers that satisfy this equation, which are known as "Pythagorean triples."
Knowing this, let's evaluate each of the statements and determine if they describe the Pythagorean theorem.
 The three side lengths of right triangles form sets called "Pythagorean triples." ✓ This is correct, and is part of the Pythagorean Theorem.
 A right triangle must have two acute angles. ✗ Although this statement is true, it is not part of the Pythagorean Theorem. This theorem focuses on the side lengths of a right triangle, not the other angles in a right triangle.
 If a triangle is a right triangle, the side lengths $a$, $b$, and $c$, will satisfy the equation $a^2 + b^2 = c^2$. ✓ This is correct, and is part of the Pythagorean Theorem.
 The hypotenuse will always be the longest side of a right triangle. ✗ Although this statement is true, it is not part of the Pythagorean Theorem. It can be proved using the Pythagorean Theorem, though!

Determine if the side lengths are a Pythagorean triple.
HintsRemember that the Pythagorean Theorem can be represented as an equation that uses the squares of the side lengths of a triangle.
The Pythagorean triples must not include fractions or decimals.
The set of side lengths is a Pythagorean triple, if they satisfy the equation $a^2 + b^2 = c^2$. This means that the left hand side of the equation must equal the right hand side.
SolutionThe equation given by the Pythagorean Theorem is $a^2 + b^2 = c^2$. Integers that satisfy these equations are known as "Pythagorean triples."
We are given the side lengths of the triangle: 8, 15, and 17. All being whole numbers, they are definitely also integers. So if the set of numbers satisfies the equation $a^2 + b^2 = c^2$, then it must be a Pythagorean triple.
The value $c$ is the length of the hypotenuse, which is the longest side. It is also the side across from the right angle. Therefore this side is 17 feet long. Either of the other two sides can act as $a$ or $b$, since they are interchangeable.
Let's assign the values $a = 8$, $b = 15$, and $c = 17$.
Substituting these values in, we get:
$a^2 + b^2 = c^2$
$8^2 + 15^2 = 17^2$
$64 + 225 = 289$
$289 = 289$
The left and right hand sides of the equation are equal. This means that the values satisfy the equation. We can see that this triangle does have side lengths that are a Pythagorean triple.

Find the areas.
HintsHow can you use the Pythagorean Theorem to help you with this question?
The area of each square that is connected to a side represents the literal "square" of that side length. This is equal to the side length, squared.
What is the relationship between the square of each side length?
You can use the equation $a^2 + b^2 = c^2$ to find the area of the square that is attached to the side that has an unknown length.
SolutionIn each of the two cases, we have a right triangle, and we know the lengths of two sides. We must find the area of the square that is connected to the hypotenuse. The area of each square that is connected to a side represents the literal "square" of that side length. This is equal to the side length, squared. We do not know the length of the hypotenuse, but there is another way to find this area.
From the Pythagorean Theorem, we know that:
$a^2 + b^2 = c^2$
We know that $c^2$ represents the area that we must find. We know the side lengths $a$ and $b$.
$a^2 = 3^2$
$a^2 = 9$
$b^2 = 4^2$
$b^2 = 16$
Now we can find $c^2$:
$a^2 + b^2 = c^2$
$9 + 16 = c^2$
$25 = c^2$
Similarly, for the second triangle...
$a^2 = 36$
$b^2 = 64$
$100 = c^2$

Decide if the ladder fits.
HintsRemember: the hypotenuse is always the longest side of the a right triangle.
If the equation is satisfied by the given values, then the ladder is the perfect length to fit between the ground and the roof, with the base of the ladder sitting 10 feet from the cottage.
In this question we move straight from the equation $a^2 + b^2 = c^2$, to the square of the values we substitute in. For example, if we had $a = 3$, $b = 4$, and $c = 5$, we would write:
$a^2 + b^2 = c^2$
$9 + 16 = 25$
By doing this, we are skipping the middle step:
$3^2 + 4^2 = 5^2$
SolutionThe ladder, the cottage, and the ground form a right triangle. We are certain about the length of two of the sides of this triangle. We know that the cottage is 24 feet tall. And we know that the bottom of the ladder must sit at least 10 feet from the base of the cottage. The farther away from the cottage the base of the ladder is placed, the longer the ladder will need to be. Let's assume we place the base of the ladder exactly 10 feet from the cottage, so that Damo is able to use the shortest possible ladder.
If the ladder is the correct length, then this set of side lengths should satisfy the Pythagorean theorem, $a^2 + b^2 = c^2$. We know that $c$ should be the hypotenuse. We can see that the ladder, which is 26 feet long, is opposite the right angle. Additionally, the ladder forms the longest side of this right triangle. Therefore it must be the hypotenuse. The other two sides can be labelled $a$ and $b$ interchangably.
$a = 10$
$b = 24$
$c = 26$
By substituting the values in, and simplifying the equation, we can check if the equation is satisfied by these values:
$\begin{array}{rclcl} a^2 + b^2 & = & c^2 &&\text{subsituting values} \\ 10^2 + 24^2 & = & 26^2 \\ 100 + 576 & = & 676 \\ 676 & = & 676 &&\text{✓ the two sides are equal} \\ \end{array}$
The two sides of this equation are equal. Therefore the values do satisfy the equation, and the ladder is the correct length.

Identify the right triangles.
HintsHow can you determine if a triangle is a right triangle using the Pythagorean Theorem?
What equation can you use to check if a triangle is right, using it's side lengths, $a$, $b$, and $c$?
If a triangle's side lengths, $a$, $b$, and $c$, satisfy the equation $a^2 + b^2 = c^2$, then it is a right triangle.
SolutionWe know that if a triangle is right, it's side lengths, $a$, $b$, and $c$, must satisfy the equation:
$a^2 + b^2 = c^2$
We are given the side lengths for each triangle. Let's use the equation to check if the triangles are right angle triangles.
The side lengths of the first triangle are 6, 8, and 10. We know that the value for $c$ must be the longest side of the triangle.
So let's assign the values $a = 6$, $b = 8$, and $c = 10$.
Putting these values into the equation gives us:
$6^2 + 8^2 = 10^2$
$36 + 64 = 100$
$100 = 100$
Since the right hand side is equal to the left hand side, the values of $a$, $b$, and $c$ for this triangle satisfy the equation. That means that this is a right triangle!
Similarly, for the other triangles, we arrive at:
$a = 9$, $b = 40$, $c = 41$:
$81 + 1600 = 1681$ ✓ The left and right sides of this equation are equal, so the triangle is right.
$a = 25$, $b = 60$, $c = 65$:
$625 + 3600 = 4225$ ✓ The left and right sides of this equation are equal, so the triangle is right.
$a = 11$, $b = 60$, $c = 61$:
$121 + 3600 = 3721$ ✓ The left and right sides of this equation are equal, so the triangle is right.
$a = 26$, $b = 36$, $c = 45$:
$676 + 1296 = 2025$ ✗ The left and right sides of this equation are not equal, so the triangle is not right.
$a = 40$, $b = 75$, $c = 85$:
$1600 + 5625 = 7225$ ✓ The left and right sides of this equation are equal, so the triangle is right.

Identify the Pythagorean triples.
HintsSometimes, the two sides of the simplified equation will not be equal. When that happens, the set is not a Pythagorean triple.
Be sure to carefully check that you have squared the terms correctly.
SolutionDamo wants to know if these sets of numbers are Pythagorean triples. We can check this using the equation $a^2 + b^2 = c^2$, where $c$ is the largest number in the set. $a$ and $b$ are the other two numbers, and are interchangeable.
Looking at the first set, $5, 4$ and $6$, let's set:
$a = 5$
$b = 4$
$c = 6$ (because $6$ is the largest number)
We can substitute these values into the equation:
\begin{array}{rclcl} a^2 + b^2 & = & c^2 &&\text{substituting} \\ 5^2 + 4^2 & = & 6^2 &&\text{simplifying} \\ 25 + 16 & = & 36 &&\text{simplifying} \\ 41 & = & 36 &&\text{✗ the two sides of the equation are not equal} \\ \end{array}
Therefore this set of numbers does not satisfy the equation, and these numbers are not a Pythagorean triple. So the statement in the question is false.
Similarly, for the second set, $12, 16$ and $20$:
$12^2 + 16^2 = 20^2$
$144 + 256 = 400$
Both sides of this equation are equal. Therefore the set is a Pythagorean triple.
And for the third set, $15, 20$ and $25$:
$15^2 + 20^2 = 25^2$
$225 + 400 = 625$
Both sides of this equation are equal. Therefore the set is a Pythagorean triple.